Vineeth Chennabhoina
Last Activity: 7 Years ago
First we find the acceleration of the body. For the first half second, the distance covered is half a meter. As we solve s= ut + 1/2at2, we get a=4m/s2. Intially the body didn’t have any velocity, but as we go through the first half second, the body gains a velocity v= u +at , as this is the velocity the body gains at the end of first half second and it has no initial velocity, substituting a=4 and t=0.5, we get v=2 m/s.
Finally, the time taken for the second half second will be
s = ut + ½at2. Here s is 0.5, u=2m/s, a=4m/s. We get a quadratic in t. Which would be
4t2 + 4t – 1 = 0 Solving by the finding roots of x, we get 1.656/8, which is 0.207 seconds, rounding it off to 0.21 seconds.