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A 74.6-kg window cleaner uses a 10.3-kg ladder that is 5.12 m long. He places one end 2.45 m from a wall and rests the upper endagainsta crackedwindowandclimbsthe ladder.He climbs 3.10 m up the ladder when the window breaks. Neglecting friction between the ladder and the window and assuming that the base of the ladder does not slip, find (a) the force exerted on the windowby the ladder justbeforethe window breaks and (b) the magnitude and direction of the force exerted on the ladder by the ground just before the window breaks.

Radhika Batra , 9 Years ago
Grade 11
anser 1 Answers
Kevin Nash

Last Activity: 9 Years ago

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Round off to three significant figures,
Fw = 269 N
Therefore, the force exerted by the ladder on the window is 269 N .


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Therefore, the vertical force exerted by the ground on the ladder is 832 N.
The horizontal force from the ground is equal to the force Fw, therefore
Fx = 269 N

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