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A hollow cylinder with inner radius R, outer radius 2R and mass M is rolling with speed of its axis v.what is its kinetic energy?

zuhair , 6 Years ago
Grade 12th pass
anser 3 Answers
Eshan

Last Activity: 6 Years ago

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Abhimanyu singh

Last Activity: 6 Years ago

Well the above answer is wrong the moment of inertia will be 
1/2m(r1^2 + r2^2)         where  r1=r , r2=2r 
So MOI is 5/2mr^2 

Shubham Singh

Last Activity: 5 Years ago

Since it's a hollow sphere so rings moment of inertia will be considered so moi is m[r1^2+r2^2] 
Now r1=R and r2=2R put these values in kinetic energy formula 

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