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A particle is executing SHM. If its amplitude is 2m and periodic time 2 seconds. Then calculate the meximum velocity of the particle

Sher Khan , 7 Years ago
Grade 12th pass
anser 1 Answers
Shailendra Kumar Sharma

Last Activity: 7 Years ago

 
The maximum velocity is \omega A Where \omega is angular velocity \omega =\frac{2\Pi }{T} Since T=2 secThus \omega =\Pi  and given Amplitude A=2so maxium velocity will be 2\Pi m/s

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