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A particle moves along a straight line OX .at a time t the distance x of the particle from Ois given by x=40 +12t-t^3.how long would the particle travel before coming to rest

Preethi , 6 Years ago
Grade 12th pass
anser 2 Answers
Arun

Last Activity: 6 Years ago

We have equationx=40+12t-t^3When t=0Then x=40 nowdx/dt = 12-3t^2 when velocity is zero then t=2When t=2 then x=56 now we can find how long object move before come to zero 56-40=16m
 
 
 

Saurav

Last Activity: 6 Years ago

AS EQUATION OF DISTANCE IS GIVE AS A FUNCTION OF T , DIFFERNTIATE THE EQ. WRT  T ON BOTH THE SIDE .
IT WILL GIVE YOU VELOCITY AS A FUNCTION OF TIME T AS SHOWN
 
 
WHEN BLOCK IS AT REST IT VELOCITY =0 
THEREFORE PUT V=0 YOU WILL GET T=2 SECOND 
NOW BBE CAREFUL
AT T=0
THE OBJECTS POSITION IS NOT 0
SO PUT T=0 IN EQUATION OF POSITION
YOU WILL GET 40
NOW, PUT T=2 IN EQUATION OF POSITION
YOU WILL GET 56
THERFORE DISTANCE TRAVELLED=56-40=16
THE UNIT OF THIS DEPENDS ON UNITS USED IN  QUESTION
THANK YOU
 

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