A particle moves along a straight line with its velocity related to position as v=-alpha x² (where alpha=constant) If at t=0 and v=0 then find the following i) Acceleration in terms of displacement ii) Acceleration in terms of time
Harsh Lalwani , 3 Years ago
Grade
1 Answers
Vibekjyoti Sahoo
Last Activity: 3 Years ago
Given x2=2+t Now differentiating this equation with respect to time we get ,
2xdtdx=1v=dtdx=2x1
Now again differentiating equation A with respect to dx we get vdxdv.dtdx=2x1dx
vdtdv=−2x21
dtdv=−2x21(2x1)=−4x31
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