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If vectors A= cos Omega t i + sin Omega t j and B = cos Omega t/2i + sin Omega t/2 j are function of time then the value of the at which they are perpendicular to each other

Payal Pradhan , 6 Years ago
Grade 11
anser 3 Answers
Deepak Kumar Shringi

Last Activity: 6 Years ago

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Prashant Chaudhary

Last Activity: 6 Years ago

A perpendicular to B  hence A.B=0
Coswtcoswt/2+sinwtsinwt/2=0
(cosA-B=cosACosB+sinAsinB) therefore
Cos(wt-wt/2)=0
Wt/2=π/2
t=π/w 
 
 

ankit singh

Last Activity: 4 Years ago

If A vector and B vector are orthogonal then the angle between them will be 90.
Thus the resultant time =>
T = √( A^2 + B^2 + 2AB×cos¢)
= √{ (cos^2wt + sin^2wt) + (cos^2(wt/2) + sin^2(wt/2)) + 0 }
= √(1 + 1)
= √2
T = √2.

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