Arun
Last Activity: 7 Years ago
Dear student
Partial pressure of N2 = 0.001 atm,T = 298 K,V = 2.46 dm3.From ideal gas law : pV = nRTn= pV/RT(N ) 0.001 *2.462/ 0.082 *298 = 10-7No. of molecules of N2 = 6.023 ´ 10^23 ´* 10-7= 6.023 ´ *1016Now, total surface sites available= 6.023 ´* 10^14 *´ 1000= 6.023 * 1017Surface sites used in adsorption = 20/100*6.023 ´* 10^17= 2 ´ *6.023 ´ 10^16Sites occupied per molecules = Number of sites/Number of molecules= 2* 6.023* 10^16/6.023 10^16 = 2
Regards
Arun (askIITians forum expert)