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Q56) a trolley freefalling on inclined plane as shown in figure.the angle of stringof pendulum with ceiling of trolley is..

Sahil khan , 9 Years ago

Grade 12th pass

3 Answers

prince

Last Activity: 7 Years ago

As given the trolley is falling freely.That means the acceleration due to pseudo force will be equal to g( gravity)Now as the trolley falls freely it will experience a psedoforce in the opposite direction of its motion. MgsinA = Mg( MgsinA is due to inclined plane) Therefore. SinA = 1 or A = 90

Yuvii

Last Activity: 5 Years ago

question is incomplete. A complete question is ----->A trolley is falling freely on inclined plane as shown in the figure. The angle of string of pendulum with the ceiling of trolley is (α) equal to

(1) θ° (2) 90° – θ° (3) 90° (4) 0°

answer : option (3) 90°

explanation : Let T is the tension acting on trolley.

so, component of tension along the inclined plane is .

if m is the mass of system of trolley,

then, component of weight along the inclined plane is

acceleration of the trolley = acceleration of the bob in the trolley as bob is in the equilibrium in frame of the trolley.

so, net force along the plane,

for free falling on inclined plane, a = along the plane.

so,

hence, option (3) is correct

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,

Please find the answer to your question.

Question is incomplete. A complete question is ----->A trolley is falling freely on inclined plane as shown in the figure. The angle of string of pendulum with the ceiling of trolley is (α) equal to

(1) θ° (2) 90° – θ° (3) 90° (4) 0°

answer : option (3) 90°

explanation : Let T is the tension acting on trolley.

so, component of tension along the inclined plane is .

if m is the mass of system of trolley,

then, component of weight along the inclined plane is

acceleration of the trolley = acceleration of the bob in the trolley as bob is in the equilibrium in frame of the trolley.

so, net force along the plane,

for free falling on inclined plane, a = along the plane.

hence, option (3) is correct

Thanks and regards,

Kushagra

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