Sarang
Last Activity: 6 Years ago
Pressure difference between sea level and the hill would be
dP1 = dh1 X ρm X g (1)
where dh = h1 (sea level mercury height = 75 cm) - h2 (hill top mercury height = 50 cm)
ρm is the density of mercury
and the pressure difference in atmospheric pressure would be
dP2 = dh2 X ρa X g (2)
where dh2 is the height of the hill, ρa is the density of air
now, we know that (1) = (2), so
dh1 X ρm X g = dh2 X ρa X g
by substituting appropriate values and rearranging, we get
dh2 = 0.25 X (ρm/ ρa) = 0.25 X 104 m
or dh2 = 2500 m
thus, the height of the hill is
dh2 = 2500m = 2.5 km
