Flag Mechanics> Three identical rods each of mass 'm' and...
question mark

Three identical rods each of mass 'm' and length 'l' form an equilateral triangle moment of inertia about one of the side is ?

Ass satwik , 7 Years ago
Grade 9
anser 4 Answers
Arun

Last Activity: 7 Years ago

It is 2ml^2/3
as about axis of rotation moment of inertia would be 0
moment of inertia of rod about axis is ml^2/3
therefore moment of inertia of triangle will be (about one of the side)
ml^2/3+ml^2/3+0=2ml^2/3
 
Ass satwik

Last Activity: 7 Years ago

How ml^2/3?
Ritika Chitlangia

Last Activity: 6 Years ago

it is ml2/2
I = (ML2sin260*)/3 + (ML2sin260*)/3
I = ML2/2
Abhinav Srivastava

Last Activity: 6 Years ago

As one of the rod acts as axis so moment of inertia about other 2 rods have to be calculated,
Two rods each of mass m could be substituted for one rod of mass 2m but of length √3l/2 and then moment of inertia can be calculated as for a uniform rod rotated from one end; 
2m×(√3l/2)^2÷3 = ml^2/2
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments