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Two objects of masses m and 2m are connected by a mass less string passing over a fixed smooth pulley. The acceleration of heavier mass wrt the lighter mass is(1) 8g/3(2) 4g/3(3) 2g/3(4) zero

Vikash Kumar Singh , 8 Years ago
Grade 12th pass
anser 1 Answers
shreya

Last Activity: 8 Years ago

In object of mass m2..F=2mg-T=>2ma ------(eq1) (as motion is downward)In object of mass m1..F=T-mg=>ma -------(eq2)(as motion is upward)Solving eq1 and eq2,We get,a=g/3As, g/3 is the acceleration downwards; so the accleration upwards will be (-g/3)And relatively,a(of mass 2m) - a (of mass m) = g/3 - (-g/3) =>2g/3
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