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Use identities to solve of a+b+c=0 then a3 + b3 + c3 = 3abc

Fahad , 6 Years ago
Grade 10
anser 1 Answers
Arun

Last Activity: 6 Years ago

a^3 + b^3 + c^3 - 3abc = (a+b+c) (a^2 + b^2 + c^2 - ab - bc -ca)
So if a+b+c = 0 
then a^3 + b^3 + c^3 - 3abc = 0
So a^3 + b^3 + c^3 = 3abc
 
now in your question take lcm
 
then
l^ + m^3 + n^3 – 3 l^3 m^3 n^3 = 0
 
now you can do yourself

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