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Sol. a) When λ = 400 nm Energy of photon = hc/λ = 1240/400 = 3.1 eV This energy given to electron But for the first collision energy lost = 3.1 ev * 10% = 0.31 ev for second collision energy lost = 3.1 ev * 10% = 0.31 ev Total energy lost the two collision = 0.31 + 0.31 = 0.62 ev K.E. of photon electron when it comes out of metal = hc/λ – work function – Energy lost due to collision = 3.1 ev – 2.2 – 0.62 = 0.31 ev b) For the 3rd collision the energy lost = 0.31 ev Which just equative the KE lost in the 3rd collision electron. It just comes out of the metal Hence in the fourth collision electron becomes unable to come out of the metal Hence maximum number of collision = 4.
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