Kuldeep Pal
Last Activity: 8 Years ago
In Regular Hexagon ABCDEF;
Let AB = a and BC = b.
since AD is parallel to BC and AD = 2BC. Therefore,
AD = 2b.
In Triangle ACD, we have
AC + CD = AD
CD = 2b – (a + b) = b - a
CE = CD + DE = b – a + (-a) = b – 2a.
One thing should keep in mind the BOLD and Capital Letters written are All VECTORS and in Same ORDER as written.