Samyak Jain
Last Activity: 6 Years ago
A slight mistake is there in the above answer.
The correct value is P = 5.39 x 10 –11.
Ans. of attachment :
We know that force on a negative charge or acceleration of a negative charge is opposite to the electric field.
So, if the acceleration of electron is eastward, then the electric field is westward.
Let a, m and e be the acceleration, mass and charge of the electron,
F be the force due to electric field exerted on it and
E be the magnitude of the electric field. Then,
F = e.E and F = ma
e.E = ma
E = ma / e
Putting the respective values, we get E = (9.1 x 10–31 kg)(1.84 x 109 m/s2) / (1.6 x 10–19 C) (approx.)
E = 10.465 x 10–3 N/C = 1.0465 x 10–2 N/C
Thus, magnitude and direction of electric field is 1.0465 x 10–2 N/C and west respectively.
