The electric field at a point associated with a light wave is E = 100V/m sin [3.0 × 1015s−1t] sin [6.0 × 1015s−1t]. If this light falls on a metal surface havingworkfunction of 2.0 eV, what will be the maximum kinetic energy of the photoelectrons?
Amit Saxena , 10 Years ago
Grade upto college level
1 Answer
Jitender Pal
Last Activity: 10 Years ago
Sol. E = 100 sin[3 * 10^15 s^–1t] sin [6 * 10^15 s^–1t]rn= 100 ½ [cos[9 * 10^15 s^–1t] – cos [3 * 10^15 s^–1t]rnThe w are 9 * 10^15 and 3 * 10^15rnfor largest K.E.rnf base max = w base max/2π = 9 * 10^15/2πrnE - ∅ base 0 = K.E.rn⇒ hf = ∅ base 0 = K.E.rn⇒ 6.63 * 10^-34 *9 * 10^15/2π * 1.6 * 10^19 – 2 KErn⇒ KE = 3.938 ev = 3.93 ev.
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