Navjyot Kalra
Last Activity: 10 Years ago
Given λ’ = λ – 26 pm, V’ = 1.2 V
Now, λ = hc/ev , λ’ = hc/ev’
Or λV = λ’V’
⇒ λV = (λ – 26 * 10^-12)* 1.5 V
⇒ λ = 1.5 λ – 1.5 * 26 * 10^–12
⇒ λ = 39* 10^-12/0.5 = 78 * 10^12 m
V = hc/eλ = 6.63 * 3* 10^-34* 10^8/1.6 *10^-19 * 78* 10^-12 = 0.15937 * 10^5 = 15.93 * 10^* V = 1593 KV.