An organic compound C5H9Br (A) which readily decolourises bromine water and cold alkaline KMnO4 solution gives C5H11Br (B) on catalytic hydrogenation. The reaction of A with alcoholic KOH first and then with NaNH2 produces C with evolution of NH3. C reacts with Lindlar’s catalyst to give D and on reaction with Na in liquid NH3 produces E. D and E are isomers. The compound A is:a. CH3CH2CH=C(Br)CH3b. CH3CH2-C(Br)=CHCH3c. Both a &b d.Neither a nor b

SUYASH , 5 Years ago

Grade 11