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100ml100ml of a liquid contained in an insulated container at a pressure of 11 bar. The pressure is steeply increasedto 100100 bar. The volume of the liquid is decreased by 1ml1ml at this constant pressure. Find theΔH &ΔU....

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Aiswarya Ram Gupta , 13 Years ago
Grade 12
anser 2 Answers
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vijesh jayan

Last Activity: 13 Years ago

V1=100ml & V2=?,

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P1=1bar & P2=100bar

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ΔH=ΔU+nRT

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BY CHARLES LAW

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P1V1=P2V2

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1*100=100*V2

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100/100=V2

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V2=1ml

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IT IS AN INSULATED CONTAINER SO NO TRANSFER OF HEAT TAKES PLACE

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THEREFORE ΔU=0

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ΔH=0+nRT => ΔH=nRT

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PV=nRT [IDEAL GAS EQUATION]

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P1-P2*V1-V2=1-100*100-1=-99*99=-9801

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IS WHAT I THINK SO

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I AM NOT SURE

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ENQUIRE OR ASK SOME ONE ELSE

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Aiswarya Ram Gupta

Last Activity: 13 Years ago

thnx...............

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