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A Sample of an ideal gas is expanded 11 m3tom^3to 33 m3m^3 in a reversible process for which P=KV2P=KV^2,with K=6K=6 bar/m6bar/m^6.work done by the gas is

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rajat agarwal , 15 Years ago
Grade 11
anser 3 Answers
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Rohith Gandhi

Last Activity: 15 Years ago

Dear Rajat,

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first converting all the parameters in SI units, i.e. unit of constant, K = 6 bar/m^6

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1 bar = 10^5 N/m^2, => K = 6X10^5 N/m^8

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so we can find out work from the equation,

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5556-2218_8202_work done.bmp

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rajat agarwal

Last Activity: 15 Years ago

thanks rohith bhaiya.but p is not equal yo K/V^2.you had solved it that way.but anyways i get the answer .Thanks a lot!!!!!!!!!!!!11i wish u help me in near future too.

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shefali sharma

Last Activity: 14 Years ago

if u still want some answer then integrate KV^2dV limits fron 1 to 3

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