How many atoms do mercury vapour molecules consist of if the density of mercury vapour relative to air is 6.92? The average mass of air is 29g/mol
anil phukan , 11 Years ago
Grade 12
1 Answers
Sunil Kumar FP
Last Activity: 10 Years ago
(density of mercury vapour/density of air) =6.92 In a given volume mass of mercury vapour/mass of air) =6.92 mass of mercury vapour =6.92*29 g/mole =200.68 g/mole therefore number of mercury molecule =Na*200.68 atoms Na is the avagadro number =6.023*10^23*200.68 atoms =1.208*10^26 atoms
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