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A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57um.calculate the rate of emission of quanta per second

Ujwala Sharma , 6 Years ago
Grade 12th pass
anser 1 Answers
Khimraj

Last Activity: 6 Years ago

Power of bulb, P = 25 Watt = 25 Js–1
energy of photon 
E = hc/\lambda = 34.87*10-20 J
rate of emission of quanta per second = P/E = 7.2*1019 s-1
Hope it clears.

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