Rishi Sharma
Last Activity: 4 Years ago
Dear Student,
Please find below the solution to your problem.
a)we have mvr=nh/2pi
r=a0 =.529A0
v=nh/2pimr =2.18*10^6 m/s,
here for first bohr orbit,n=1
b)debroglie wavelength =h/mv
=6.6*10^-34/9.1*10^-31*2.18*10^6
=3.3A0
c)For 2 p value of l=1
Orbital angular momentum = sqrt(l(l+1))h/2pi
= sqrt2 h/2pi
Thanks and Regards