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A compound is formed by two elements M and N. The element N forms ccp and atoms of M occupy 1/3rd of tetrahedral voids. What is the formula of the compound?

prasanjeet kumar , 10 Years ago

Grade 8

4 Answers

Pankaj

Last Activity: 9 Years ago

In CCP crystal
Number of N atoms (Z) = 4
Number of tetrahedral voids = 2Z = 8
Number of M atoms = 1/3rd of 8 = 8/3
N:M = 4: 8/3
Formula, = N₁₂M₈
or
N₃M₂

Anirban Laha

Last Activity: 7 Years ago

Since element M are in ccp arrangement, the number of M per unit cell=4The number of tetrahedral void=8But only 1/3rd is occupied by N, therefore 8×1/3rd Hence the formula of the compound is M4N8/3=M12N8or M3N2

Prashant Gupta

Last Activity: 6 Years ago

The number of tetrahedral voids formed is equal to twice the number of atoms of element N and only 1/3rd of these are occupied by the atoms of element M . Hence the ratio of the number of atoms of M and N is 2 * (1/3):1 or 2:3 and the formula of the compound is M2N3.

Yash Chourasiya

Last Activity: 4 Years ago

Dear Student

The ccp lattice is formed by the atoms of the element N.
Here, the number of tetrahedral voids generated is equal to twice the number of atoms of the element N.
According to the question, the atoms of element M occupy (1/3)^rdof the tetrahedral voids.
Therefore, the number of atoms of M is equal to (2/3)^rd of the number of atoms of N.

Therefore, ratio of the number of atoms of M to that of N is M: N
= 2/3 : 1
= 2 : 3
Thus, the formula of the compound is M₂N₃.

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya