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At what minimum PH will 10-3 mol of Al(OH)3 go in to solution (V=1L) as Al(OH)4- and at what minimum PH it will dissolve as Al+3?Given: Al(OH)4- == Al+3+4OH-Keq=1.3* 10-34 Al(OH)3 ==Al+3+3OH-Keq=5* 10-33

rahul , 8 Years ago
Grade 12th pass
anser 1 Answers
Rituraj Tiwari

Last Activity: 4 Years ago

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