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calculate ebullioscopic constant for water. The heat of vaporization is 40.685 kJ/mol

Piyush Upadhyay , 7 Years ago
Grade 11
anser 2 Answers
S N RAO

Last Activity: 7 Years ago

Kf  =MRTf2/1000DHv
Kf  =  18*8.314*273*273
          1000*40.685*1000
 Kf  = 11153.41     
          40.685*1000000                                            Kf  =0.274 
M molecular mass of water Tf is freezing point of water in kelvin
 
S N RAO

Last Activity: 7 Years ago

Kb = MRTb*Tb
        1000*DHv
Kb =18*8.314*373*373
        1000*40.685*1000
Kb= 20820933.108
       40.685*1000000
Kb=0.512   M is molecular mass os water  Tb is boiling point of water
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