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calculate the potential of hydrogen electrode whose ph=10

Simran Bhatia , 10 Years ago
Grade 11
anser 1 Answers
Akshay Meena

Last Activity: 10 Years ago

According to Nerst equation E = E0-2.303(RT/nF)logQ Here : E0 = 0 [H+]=10^-10, Q = 10^10 as Pressure of H2= 1 atm and n = 1 gives where R = 8.314, T = 298 K generally), F = 96500 C E = 0-2.303(RT/F)(10)=-23.03RT/F = -0.591 V, Thanks & Regards Akshay Meena, askIITians Faculty M.Tech, IIT Kharagpur

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