Physical Chemistry> Consider the reaction: Cr2O72– + 14H+ + 6...

Consider the reaction: Cr2O72– + 14H+ + 6e– ? 2Cr3+ + 7H2O What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr2O72–?

prasanjeet kumar , 11 Years ago

Grade 8

4 Answers

Sunil Kumar FP

Last Activity: 11 Years ago

the quantity of electricity in coulombs needed to reduce 1 mol of Cr2O72- 204-1209_Wed Aug 20 15-34-52.jpg

shashidhar

Last Activity: 6 Years ago

2x-14=-2

2x=12

x=6

~6×96500=579000C is the charge required to reduce the 1 mol of cr2o72-, the amount of charge is required to reduction is 579000C

Kushagra Madhukar

Last Activity: 5 Years ago

Hello student
As mentioned, the balanced chemical reaction is-
Cr₂O₇^2– + 14H⁺ + 6e^–→ 2Cr³⁺ + 7H₂O

As per the reaction, 1 mole of Cr₂O₇^2- is reduced by 6 moles of electrons = 6 Faraday

= 6 x 96500 C

= 579000 C
Hope it helps.
Regards,
Kushagra

Yash Chourasiya

Last Activity: 5 Years ago

Dear Student

The balanced chemical reaction is-
Cr₂O₇^2–+ 14H⁺+ 6e^– → 2Cr³⁺+ 7H₂O
As per the reaction, 1 mole of Cr₂O₇^2-is reduced by 6 moles of electrons = 6 Faraday
= 6 x 96500 C
=579000 C

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya