Physical Chemistry> Same electric charge is passed through aq...

Same electric charge is passed through aqua solution of HCL and CuSo4. if 12 gram of H2 is liberated find the mass of copper deposited1.402 g2.360 g3.381 g 4.369 g

Junaid , 5 Years ago

Grade 12

4 Answers

Arun

Last Activity: 5 Years ago

W1 = (A1 X I X t) ÷ (n1 x 96500)
W1 is mass of H2
12 = (1 X I X t) ÷ (2 x 96500)
12 x 193000 = I X t ---------------- equation 1
W2 = (A X I X t) ÷ (n2 x 96500)
W2 is the mass of Cu
W2 = (63.5 X 12 x 193000) ÷ 193000 = 762g/2 = 381

Vikas TU

Last Activity: 5 Years ago

2 mole of electron will liberate 1 mole of H2 gas

Mole of H2 liberated = 12/2 = 6

To liberate 6 mole of e we require 12 mole of e

To liberate 2 mole of e we need 1 mole of cu

12 mole of e will deposit 6 mole of cu

Mass of cu = 6* 63.5 = 381

Shafi Shaik

Last Activity: 4 Years ago

12 moles of H₂ electron deposit 12/6=6 mole Cu.Hence, mass of copper deposited will be 6×63.5=381gram.

Anuranjan

Last Activity: 2 Years ago

Amount of H2 liberated = 12g

Moles of electron required to liberate 12g of H2 = given mass/molar mass = 12/2=6

Now , 6 mole of H2 require 12 mole of electron.

For 2 mole of electron we require 1 mole of copper.

Hence, 12 mole of electron will deposit 6 mole of copper.

So finally , mass of copper deposited = 6× 63.5=381

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Physical Chemistry> Same electric charge is passed through aq...

Same electric charge is passed through aqua solution of HCL and CuSo4. if 12 gram of H2 is liberated find the mass of copper deposited1.402 g2.360 g3.381 g 4.369 g

Junaid , 5 Years ago

Arun

Vikas TU

Shafi Shaik

Anuranjan

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