The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. Kb for benzene is 2.53 K kg mol–1
Jayant Kumar , 11 Years ago
Grade 11
2 Answers
Sakshi
Last Activity: 9 Years ago
One can use the fact for the elevation in boiling point on the addition of a non-volatile solute. The equation to be used is
Jerin A Varghese
Last Activity: 5 Years ago
Tb = 354.11 K
T0b = 353.23 K
Kb = 2.53 K
wsolute = 1.8 g
wsolvent =90 g
Tb = Tb - T0b
=354.11 – 353.23
=0.88 K
Tb = Kb xwsolute ÷ wsolvent x Mo
Mo = 2.53 K x 1.8 g 90 g x 0.88 K
= 0.0575 kg/mol
= 57.5 g/mol
= 58 g/mol
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