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The distance s meter covered by a body in t second is given by s = 3t^3 - 8t +5, the body will stop after 1. 1s2. 3/4s3. 4/3s4. 4s

Prachi , 7 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

The body would stop after its final
velocity becomes zero.
Hence, velocity = ds/dt => 9t^2 – 8 = 0 
t^2 = 8/9
t = 2root2/3 seconds => 0.942 seconds => approx. 1 second.

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