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The rate of the chemical reaction doubles for an increase of 10K in absolute temperature from 298K. Calculate Ea?

prasanjeet kumar , 10 Years ago
Grade 8
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Sunil Kumar FP

Last Activity: 10 Years ago

The rate of the chemical reaction doubles for an increase of 10K in absolute temperature from 298K
log(k2/k1)=Ea/2.303 R(1/T1-1/T2)
it inpleis from the above value that
log2=Ea/2.303*8.314(1/298-1/308)
Ea=53KJ
The energy of activation is the minimum energy for a reaction to have in order to proceed in a given direction

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