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What volume of chlorine at STP is required to liberate all iodine from 200ml of 0.2M KI solution?

karan patel , 8 Years ago
Grade 11
anser 1 Answers
Vikas TU
Dear Student,
200 ml of 0.2 M KI arrangement has 0.2/5= 0.04 mol KI 
Here the adjusted condition is 
2KI+ Cl2 = 2KCl + I2 
In this way, for 2 moles KI there is need of 1 mole Cl2 
For 0.04 mole it is 0.02 mole 
Volume is 0.02x22.4 lit = 0.448 lit (STP).
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
Last Activity: 8 Years ago
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