Write the structures of the following organic halogen compounds . (i) 2-Chloro-3-methylpentane (ii) p-Bromochlorobenzene (iii) 1-Chloro-4-ethylcyclohexane (iv) 2-(2-Chlorophenyl)-1-iodooctane (v) 2-Bromobutane (vi) 4-tert-Butyl-3-iodoheptane (vii) 1-Bromo-4-sec-butyl-2-methylbenzene (viii) 1,4-Dibromobut-2-ene

To draw the structures of the organic halogen compounds you've listed, we need to break down each name into its components. This involves identifying the main carbon chain, substituents, and the positions of the halogen atoms. Let's go through each compound step by step.

2-Chloro-3-methylpentane

This compound has a five-carbon chain (pentane) with a chlorine atom on the second carbon and a methyl group on the third carbon. The structure can be represented as follows:

• Carbon chain: C-C-C-C-C
• Chlorine on C2
• Methyl group on C3

The structure looks like this:

       CH3
        |
    CH3-CH-CH-CH2-CH3
        |
       Cl

p-Bromochlorobenzene

This compound is a benzene ring with a bromine and a chlorine substituent. The "p" indicates that these substituents are in the para position (opposite sides of the ring). The structure is:

       Br
        |
    C6H4
        |
       Cl

1-Chloro-4-ethylcyclohexane

In this case, we have a cyclohexane ring with a chlorine atom on the first carbon and an ethyl group on the fourth carbon. The structure can be visualized as:

        Cl
         |
    C6H10
         |
        CH2-CH3

2-(2-Chlorophenyl)-1-iodooctane

This compound features an eight-carbon chain (octane) with an iodine atom on the first carbon and a phenyl group (with a chlorine substituent) on the second carbon. The structure is more complex:

       Cl
        |
    C6H4
        |
    CH3-CH-CH2-CH2-CH2-CH3
        |
       I

2-Bromobutane

Here, we have a four-carbon chain (butane) with a bromine atom on the second carbon. The structure is straightforward:

    CH3-CH-CH2-CH3
         |
         Br

4-tert-Butyl-3-iodoheptane

This compound consists of a seven-carbon chain (heptane) with a tert-butyl group on the fourth carbon and an iodine atom on the third carbon. The structure can be depicted as:

        CH3
         |
    CH3-CH-CH-CH2-CH2-CH3
         |
         I

1-Bromo-4-sec-butyl-2-methylbenzene

This compound has a benzene ring with a bromine atom on the first carbon, a sec-butyl group on the fourth carbon, and a methyl group on the second carbon. The structure is:

       Br
        |
    C6H4
        |
       CH3
        |
       CH-CH2-CH3

1,4-Dibromobut-2-ene

Lastly, this compound features a four-carbon chain with a double bond between the second and third carbons, and bromine atoms on the first and fourth carbons. The structure is:

    Br-CH=CH-CH-CH2-Br

These structures illustrate the arrangement of atoms in each compound, highlighting the positions of halogen substituents. Understanding these structures is crucial for predicting the chemical behavior and reactivity of these organic halogen compounds.