Ramesh V
Last Activity: 15 Years ago
It follows the same method as explained in your previous post,
http://www.askiitians.com/forums/Thermal-Physics/12/3572/transfer-of-heat.htm
solutions as follws:
K1:K2 = 1:4
K1(100-T) = K2(T-0)
Temp. of interface = 20 C
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IIT Kgp - 2005 batch