Umar Farooq
Last Activity: 5 Years ago
Its initial velocity u=16.3 (cos 27.4) i +16.3 (sin 27.4)j
Initial kinetic energy KEinitial=0.5 mu2 = 0.5 x 0.0524 x 16.32 = 69.6 J
As there’s no force along horizontal direction vx=16.3 (cos 27.4)=14.47
vy= u (sin 27.4) + gT
T= 2u sin (27.4) /g
vy= 3u (sin 27.4)
v= 14.47 i + 22.5 j
v= 26.75
KEfinal =0.5 mv2 =0.5 x 0.0524 x 26.752=187.48 J