Flag Thermal Physics> a carnot engine whose efficiency is 50 %,...
question mark

a carnot engine whose efficiency is 50 %,if sink temperature is decreased by 100% then efficiency will be 70% ,find the temperature of source

ritik , 7 Years ago
Grade 12th pass
anser 1 Answers
Shailendra Kumar Sharma

Last Activity: 7 Years ago

1-Tsink/TSource =.5
How can you reduce temp by 100% 
still lets say you reduced to half 
1-(.5Tsink)/Tsource =.9
This gives 
(TSource-Tsink)/(Tso-.5Tsi) =5/9
4Tsource=(6.5) Tsink
This way you can proceed
 

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...