Kevin Nash
Last Activity: 10 Years ago
Sol. (a) A = 20 cm^2 = 20× 10^–4 m^2, T = 57°C = 330 K
E = A σT^4 = 20 × 10^–4 × 6 × 10^–8 × (330)^4 × 10^4 = 1.42 J
(b) E/t = Aσe(T base 1^4 – T base 2^4), A = 20 cm^2 = 20 * 10^-4 m^2
σ = 6 * 10^-8 T base 1 = 473 K, T base 2 = 330 K
= 20 × 10^–4 × 6 × 10^–8 × 1[(473)^4 – (330)^4]
= 20 × 6 × [5.005 × 10^10 – 1.185 × 10^10]
= 20 × 6 × 3.82 × 10^–2 = 4.58 w from the ball.