Jitender Pal
Last Activity: 10 Years ago
Sol. 1. T base 1 = 15° t base 2 = 17°c
∆t = t base 2 – t base 1 = 17 – 15 = 2°C = 2 + 273 = 275 K
m base v = 100 g = 0.1 kg m base w = 200 g = 0.2 kg
cu base g = 420 J/kg–k W base g = 4200 J/kg–k
(a) The heat transferred to the liquid vessel system is 0. The internal heat is shared in between the
vessel and water.
(b) Work done on the system = Heat produced unit
⇒ dw = 100 × 10 ^–3 × 420 × 2 + 200 × 10^–3 × 4200 × 2 = 84 + 84 × 20 = 84 × 21 = 1764 J.
(c)dQ = 0, dU = – dw = 1764. [since dw = –ve work done on the system]