Vikas TU
Last Activity: 4 Years ago
Dear Student,
Please find below the solution to the asked query:
Given that the velocity of the particle at the bottom is √9g.
Therefore, the tension in the string at the bottom is,
Tb=mg+mv^2/l=mg+9mg
⇒Tb=10 mg
Let V be the velocity of the sphere, when it is at the top of the circle, then
1/2 * m(V^2i−V^2f)=mg(2l)⇒V^2 = 9g−4g
⇒V= √5g
So, tension in the string. When it is top is,
Ttop=mVt^2/l −mg=5mg−mg
⇒Ttop=4mg
Therefore, the ratio of tension, when the sphere is at top and bottom is,
Ttop/Tbot=4mg/10mg=2/5
Hope this information will clear your doubts about the topic.
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