Deepak Patra
Last Activity: 9 Years ago
To obtain the number of moles n are present in the gas, substitute 24 J/K for ΔS, 8.31 J/mol. K for R, 3.4 L for Vf and 1.3 L for Vi in the equation,
n = ΔS/ (R ln Vf/Vi)
= (24 J/K) / (8.31 J/mol. K) (ln 3.4 L/1.3 L)
= (24 J/K) / (8.31 J/mol. K) (ln (3.4/1.3))
= 3.00 mol
From the above observation we conclude that, the number of moles n are present in the gas would be 3.00 mol.