Deepak Patra
Last Activity: 9 Years ago
To obtain the absorbed heat Q, substitute 46.2 J/K for ΔS and 132̊ C for T in the equation Q = ΔS T,
Q = ΔS T
= 46.2 J/K 132̊ C
= 46.2 J/K 132 +273 K
= 46.2 J/K 405 K
= 1.87×104 J
From the above observation we conclude that, the absorbed heat Q will be 1.87×104 J.