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An ideal undergoes a reversible isothermal expansion at 132132ºC. The entropy of the gas increase by 4646.22 J/KJ/K. How much heat is absorbed?

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Shane Macguire , 9 Years ago
Grade upto college level
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Deepak Patra

Last Activity: 9 Years ago

To obtain the absorbed heat Q, substitute 46.2 J/K for ΔS and 132̊ C for T in the equation Q = ΔS T,
Q = ΔS T
= 46.2 J/K 132̊ C
= 46.2 J/K 132 +273 K
= 46.2 J/K 405 K
= 1.87×104 J
From the above observation we conclude that, the absorbed heat Q will be 1.87×104 J.

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