Mona
Last Activity: 6 Years ago
Relation between alpha ad gammaV= L3L= L.[1+ alpha ∆T]v= L.3(1+alpha∆T)3Then, using binomial theorem(1+x)n = 1+nxTherefore, V= L.3(1+3alpha∆T)V= V.(1+3alpha∆T)V=3V.(1+Y∆T)Y=3alphaAlpha= Y/3Between alpha ad betaS= L2L=L.(1+B∆T)V= L.2(1+B∆T)2Again using binomial theorem (1+x)n=1+nxV= l.3(1+2B∆T)V=V.(1+2B∆T)V=V.(1+B∆t)B=2alphaAlpha = B/2Therefore,Alpha/1 =Beta(B)/2=Gamma(Y)/3Alpha:Beta:GammaHence solve...