Time period of a pendulum clock at 25°c is 2 seconds. If it looses 8.64 seconds per day on a day of temperature 45°c,the coefficient of linear expansion of pendulum isA2×10power−5°cB10power−5°cC5×10power−5°cD10power−6°c
Kondaveti prahakar , 7 Years ago
Grade 11
2 Answers
Subho Pal
Last Activity: 7 Years ago
T2 is directly proportional to L [T: period L: length of the pendulum]
rn
At 250C T25=2 s
rn
At 450C T45=24*3600+8.64/24*3600/2 s
rn
=2 + 8.64/12*3600 s
rn
=2.0002 s
rn
L45/L25 =2.0002/22 =1.0002=1+α.t=1+α.45-25=1+20*α
rn
or, 20*α=0.0002
rn
or, α=0.0002/20
rn
therefore, α=10-5
rn
option B10power-5 0C-1 is correct
Phanisivani
Last Activity: 4 Years ago
∆T=1/2a∆theta86400. 45-25=1/2a8.64-286400. 20=1/2a464/10086400. a=20/464×432. a=20/232×432. a=5/232×216. a=10^-5/°c approximately
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free