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Work done in converting 1 gram of ice at -10C into steam at 100C is ? A 3045 J B 6056J C 721 J

Noman , 6 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 6 Years ago

m=1gram
The change takes place as-
-10°C(ice)---0°C(ice)---0°C(water)---100°C(water)---100°C(steam)
Tip:When state changes temperature doesn't Use energy=ms?(theta) when temperature changes and energy=mL when the state changes
-10°C(ice)to 0°C(water)=ms?(theta)=5cal
0°C(ice)to 0°C(water)=mL=80cal
0°C(water)to 100°C(water)=100cal
100°C(water)to 100°C(steam)=540cal
Total=725cal=3045joules
 

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