Trigonometry> find value

sin(37) ???

Samyuktha Shankar , 14 Years ago

Grade

12 Answers

Sona Srivastava

Last Activity: 14 Years ago

in a right angled triangle with sides as 3,4,5 or 6,8,10 the angles other than the right angle are 37° and 53°
so

sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°

fgdgd

Last Activity: 7 Years ago

$fgfdg\sum \prod \Cap \setminus \lozenge \blacklozenge \blacksquare \triangle \triangleleft \gamma \varpi \mu \nu \iota \kappa \eta \zeta \omega \phi \sigma$

utpal raj

Last Activity: 7 Years ago

sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°

this is very important for exam point of view so remember this …

good luck

llol

Last Activity: 7 Years ago

sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°

is correct so do some revision on this\!!!!!!!!!!!!!!!!!!!!!

Prince Zrk

Last Activity: 7 Years ago

Remember cos as father Cos 53 =5/3 just oppositeAnd sin is reverse so 5/3=sin 37And one value is 4/5 So cos37and sin53 is for thatThanks

Aman sharma

Last Activity: 7 Years ago

Exact value of sin37° & cos37° areSin37°=0.601Cos37°=0.798°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°

Karthi

Last Activity: 7 Years ago

Its very simple construct a triangle sides 3,4,5 and mark the angle thita now one angle will be 90`,53` and 37` now by using sin and cos thita ratios we can find the angles that isSin37`= opposite / hypotaneus = 3/5Similarly :Sin53`= 4/5Cos37` = 3/5cos53`= 3/5

HJHJHJHJH

Last Activity: 7 Years ago

sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°

it is so simle

HJHJHJHJH

Last Activity: 7 Years ago

sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°

it is so simple

srry for the mistake

Chetana

Last Activity: 7 Years ago

It’s very simple construct a triangle sides 3,4,5 and mark the angle thita now one angle will be 90`,53` and 37` now by using sin and cos thita ratios we can find the angles sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°

Monalisha Nayak

Last Activity: 5 Years ago

It's so simple

sin37° = 3/5 = cos53°

sin53° = 4/5 = cos37°

tan37° = 3/4 = cot53°

tan53° = 4/3 = cot37°

A very good luck for exams

Rishi Sharma

Last Activity: 4 Years ago

Hello students,
The solution of the above problem is attached.
I hope the solution will solve all your doubts.
Being a standerd pythogorus triplet it is advisable to remember the angles and sides to enhance your speed in exams.
Thank You,
All the Best for the Exams.

645-1110_WhatsApp Image 2020-06-05 at 1.41.15 AM.jpeg