Last Activity: 14 Years ago
in a right angled triangle with sides as 3,4,5 or 6,8,10 the angles other than the right angle are 37° and 53°
so
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
Last Activity: 8 Years ago
Last Activity: 8 Years ago
Last Activity: 8 Years ago
Last Activity: 8 Years ago
Remember cos as father Cos 53 =5/3 just oppositeAnd sin is reverse so 5/3=sin 37And one value is 4/5 So cos37and sin53 is for thatThanks
Last Activity: 8 Years ago
Exact value of sin37° & cos37° areSin37°=0.601Cos37°=0.798°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
Last Activity: 7 Years ago
Its very simple construct a triangle sides 3,4,5 and mark the angle thita now one angle will be 90,53 and 37nowbyusingsinandcosthitaratioswecanf∈dthe∠stˆisSin37= opposite / hypotaneus = 3/5Similarly :Sin53=45Cos37 = 3/5cos53`= 3/5
Last Activity: 7 Years ago
Last Activity: 7 Years ago
Last Activity: 7 Years ago
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Last Activity: 4 Years ago
Hello students,
The solution of the above problem is attached.
I hope the solution will solve all your doubts.
Being a standerd pythogorus triplet it is advisable to remember the angles and sides to enhance your speed in exams.
Thank You,
All the Best for the Exams.
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Last Activity: 2 Years ago
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