suryakanth AskiitiansExpert-IITB
Last Activity: 14 Years ago
Dear abhipsa,
we know that
cos a + cos 3a + cos 5a + .. + cos(2n-1)a = sin 2na/2 sin a
In our case n = 5
therefore RHS = sin 10a / (2sina)
=>RHS = sin 2*5 *(180/11) / 2sin (180/11)
=> RHS = sin (180/11) /2 sin(180/11)
=> rhs = 1/2
hence the answer is option 3 ......1/2
GOODLUCK
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