solve for xsin4x+sin2x-sin6x=0
Rohan verma , 11 Years ago
Grade 11
Trigonometry> trigonometric-function
3 Answers
jitender lakhanpal
Last Activity: 11 Years ago
Prajwal kr
Last Activity: 11 Years ago
2cos3xsinx + 2sinxcox=0
=>sinx=0
=>x= npi...................... n is 1,2,3............
Also,
2cos3x + cosx=0
8cos3x-5cosx=0
cosx=0
=> x is (2k+1)pi/2......................................................................................
Also,
8cos2x-5=0
cosx=+-(5/8)1/2.................................................
All the above are solutions for the given equation
jitender lakhanpal
Last Activity: 11 Years ago
hi prajwal
you made a slight mistake
|
sin4x+sin2x-sin6x is not equal to 2cos3xsinx + 2sinxcox you have paired sin 4x and sin 2x then applied the identity you got 2 cos 3x sinx then what you get is 2 cos 3x sinx - sin6x so this is where you got wrong |
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