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General solution for |sinx|=cosx is....PLEASE ANSWER ASAP!!thanks!

Shreya , 6 Years ago
Grade 11
anser 3 Answers
Arun

Last Activity: 6 Years ago

Dear Shreya
 
when sinx >0
 
sin x =  cos x
 
tanx =1
 
x = n* pi + pi/4
 
similarly do this for sinx
 
Regards
Arun

Shreya

Last Activity: 6 Years ago

Thanks for answering bt I also did it the same way as you did bt the correct answer is 2nπ + π/4 (where n belongs to Integers)...
PLEASE EXPLAIN HOW?

Abhay

Last Activity: 6 Years ago

As mod us present we have to remove it hence squaring both sides,
Sin2x=cos2x
tan2x = 1
x = npi + pi/4 or npi - pi/4

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